Hey there! In this blog post, we'll walk through the process of updating deeply nested objects within object lists in Xano. We'll be using a real-world example to illustrate the steps, so you can follow along and apply the same techniques to your own projects.
Imagine you have a data structure that looks something like this:
json
{
"id": 1,
"name": "Parent Object",
"childObjects": [
{
"id": 1,
"name": "Child Object 1",
"grandchildObjects": [
{
"id": 1,
"name": "Grandchild Object 1"
},
{
"id": 2,
"name": "Grandchild Object 2"
}
]
},
{
"id": 2,
"name": "Child Object 2",
"grandchildObjects": [
{
"id": 3,
"name": "Grandchild Object 3"
}
]
}
]
}
Now, let's say you want to update the `name` property of one of the grandchild objects, like "Grandchild Object 1". How would you go about doing that? Well, you could try to manually navigate through the nested objects, but that can quickly become cumbersome and error-prone, especially if you have a large and complex data structure.
Thankfully, Xano provides a neat solution to this problem!
In Xano, you can use a combination of queries and loops to update deeply nested objects within object lists. Here's a step-by-step guide on how to do it:
js
const parentRecords = await xano.data.query('ParentTable');
js
const updatedParentObjects = [];
js
for (const parentRecord of parentRecords) {
// ...
}
js
let childLoopCounter = 1;
js
for (const childObject of parentRecord.childObjects) {
// ...
}
js
for (const grandchildObject of childObject.grandchildObjects) {
// ...
}
js
if (grandchildObject.id === 1) {
// Update the grandchild object
grandchildObject.name = 'Updated Grandchild Object 1';
}
js
parentRecord.childObjects.splice(childLoopCounter - 1, 1);
js
const updatedChildObject = {
...childObject,
grandchildObjects: [
...childObject.grandchildObjects.slice(0, childLoopCounter - 1),
updatedGrandchildObject,
...childObject.grandchildObjects.slice(childLoopCounter)
]
};
parentRecord.childObjects.push(updatedChildObject);
js
childLoopCounter++;
js
updatedParentObjects.push(parentRecord);
js
for (const updatedParentObject of updatedParentObjects) {
await xano.data.updateRecord('ParentTable', updatedParentObject);
}
And that's it! By following these steps, you can successfully update deeply nested objects within object lists in Xano. Keep in mind that the specific implementation details may vary depending on your data structure and requirements, but the overall approach should remain the same.
While the solution presented above works for updating nested objects, it's important to note that dealing with deeply nested data structures can quickly become complex and difficult to maintain. As a best practice, consider restructuring your data model to avoid such nested structures.
One approach is to break down the data into separate tables and establish relationships between them using foreign keys. This way, you can leverage Xano's built-in functionality for updating records, maintaining data integrity, and ensuring better performance.
For example, instead of nesting child and grandchild objects within a parent object, you could create separate tables for each level and establish relationships using foreign keys:
By following this approach, you can easily update individual records using Xano's `updateRecord` function, without the need for complex looping and object manipulation.
Remember, the key to building maintainable and scalable applications is to keep your data structures as simple and normalized as possible. Xano provides powerful tools to help you achieve this, so don't hesitate to explore and experiment with different data modeling techniques.
If you have any further questions or need assistance, feel free to reach out to the Xano community or contact our support team. Happy coding!
This transcript was AI generated to allow users to quickly answer technical questions about Xano.
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